In the same net ionic equation (Cu2+ + Zn -> Cu + Zn2+), the zinc (Zn) atom is:
MCQs — Electrochemistry
Practice questions for Chemistry.
An increase in an atom's oxidation number during a reaction corresponds to:
A decrease in an atom's oxidation number during a reaction corresponds to:
In the reaction 2Ca + O2 -> 2CaO, each calcium atom loses two electrons to form Ca2+. Based on this electron transfer, calcium is being:
In the same reaction (2Ca + O2 -> 2CaO), each oxygen atom gains two electrons to form O2-. Based on this electron transfer, oxygen is being:
In the reaction 4Na + O2 -> 2Na2O, sodium metal is:
In the reaction 2Al + 3Cl2 -> 2AlCl3, aluminium metal is:
In the reaction Mg + Cl2 -> MgCl2, chlorine is:
Oxidation and reduction always occur together in the same reaction because:
Since Group IIA metals characteristically form M2+ cations and Group VIA non-metals characteristically form X2- anions, in a reaction between a Group IIA metal and a Group VIA non-metal, the metal will always be:
Oxidation state (oxidation number) is defined as:
An element that shows an increase in oxidation number over the course of a reaction is being:
An element that shows a decrease in oxidation number over the course of a reaction is being:
In the reaction H2 + Cl2 -> 2HCl, chlorine's oxidation state changes from 0 to -1. Is chlorine being reduced?
In the same reaction (H2 + Cl2 -> 2HCl), hydrogen's oxidation state changes from 0 to +1. Is hydrogen being oxidized?
According to the oxidation-state rules, the oxidation state of any element in its free, uncombined form (such as Zn metal, Na metal, or H in H2 gas) is always:
According to the oxidation-state rules, in a simple monoatomic ion, the oxidation state is:
According to the oxidation-state rules, in a polyatomic (complex) ion, the sum of the oxidation states of all the atoms present equals:
According to the oxidation-state rules, the algebraic sum of the oxidation numbers of all the atoms in a neutral molecule or compound is always:
Why is the oxidation state of an atom in its free, uncombined elemental form always zero?
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